## Friday, November 28, 2014

## Saturday, November 22, 2014

The exact area can be found by integrating the function, which is the opposite of differentiation.

Suppose we want the area under the curve defined by the function f(x) = x^2 + 4x + 6 from [1, 4].

We integrate the function first. To do so we take 1/(exponent + 1)(coefficient and variable)^(exponent + 1).

So x^2 becomes (1/3)x^3

4x becomes 2x^2

and 6 becomes 6x

Put it all together we have (1/3)x^3 + 2x^2 + 6x. Now we substitute the values in the interval for x, first 4.

(1/3)(4^3) + 2(4)^2 + 6(4) = 77 1/3

Now substitute 1 for x to get

(1/3) + 4 + 6 = 10 1/3

Subtract 10 1/3 from 77 1/3 to get the final answer of 67.

## Wednesday, November 19, 2014

The velocity, v(t), is found by taking the derivative, which is the rate of change of the object.

v(t) = -9.8t

Now we can used the mean value theorem, which is [f(b)- f(b)]/(b - a) for some interval a to b in which the function is differentiable. The interval is 0 to 3, so a = 0 and b = 3

f(3) = 255.9

f(0) = 300

(255.9 - 300)/(3 - 0) = -14.7 which is the average velocity. How can velocity be negative, one might think? The object is going downward, which makes it negative. Speed can only be positive but velocity can be both positive or negative depending on the direction.

## Sunday, November 16, 2014

First, we find the critical values, which is where the slope along the curve equals 0. To get that we take the derivative, set equal to 0 and solve for x.

f'(x) (derivative) = 2x - 3.

Set equal to 0 and we see that x = 3/2 or 1.5

Now, find the y coordinate of the endpoints of the interval and of the critical point.

f(0) = 7

f(2) = 5

f(1.5) = 4.75

Therefore the maximum on the interval is at 0,7 and the minimum on the interval is (1.5, 4.75). In fact, since this is a parabola, the vertex is (1.5, 4.75), which is the minimum value of the curve.

## Monday, November 10, 2014

First you have to figure out what distance a wheel will cover in one revolution. That means we calculate the circumference of the wheel.

C= 2Pi(Radius)

C= 2(3.14)(15)

Therefore, the circumference is approximately 94.2 inches, which is 7.85 feet.

There are 52,800 feet in 10 miles. Therefore, there are 52800/7.85 = 6726 revolutions.

## Monday, November 3, 2014

We can use calculus to solve this problem.

The volume of a cone is 1/3(Pi)(Radius squared)(Height)

To solve this, use implicit differentiation. First we need to substitute a value for r in terms of h. The we know that 5/12 = r/h, therefore r = (5/12)h.

V = (1/3)Pi(5/12 h)^2(h)

= (1/3)Pi(25/144)h^3

Differentiate to get

V' = (1/3)Pi(75/144)h^2(h')

We know V' = 10, h = 8. Substitute those values into the equation and solve for h'.

10 = (1/3)Pi(75/144)(8)h'

10 = 4.36h'

h' = 2.29

Therefore, the depth of the tank is rising at the rate of 2.29 cubic feet per minute.

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