If n is an integer and n2
is a positive integer, which must also be positive?
a. n2 + n
b. n2 – m3
c. 2n2 – n
d. n3 + n
e. 2n3 + n
At
first glance a,b and c all seem reasonable because squaring any
number will give a positive answer. But answer b wont always work
because if n is positive, n3
will be greater than or equal to n2.
So when subtracting it from n2
you will either get 0, if n is 1 or negative if n >1.
For
answer a, if n = -1, then n2
+ n = 0, which does not give a positive answer either.
Therefore
answer c is the correct answer.
Any
positive number squared times 2 will be greater than the number
itself so 2n2
– n > 0 for any positive number n.
If
n is negative, 2n2
is positive and subtracting a negative is like adding a positive, so
2n2
– n > 0 for any negative number n as well.
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