To graph f(x) = √x, we'll set up a table of values.

For x = 1, f(1) = √1 = 1

x = 4, f(4) = √4 = 2

x = 9, f(9) = √9 = 3

x = 16, f(16) = √16 = 4

We would plot this on a rectangular coordinate system with the horizontal axis being x, the vertical axis being f(x). Note that the vertical axis on a rectangular coordinate system is generally the y axis. Notice we used values for x that are perfect squares. They are much easier to graph.

Note that we only used the principal square root for the values of f(x). The reason for this will be noted

after the graph. Recall that the square root has both positive and negative values (ie, √4 = 2 and -2). But the reason we did not use the negative values on the graph is because we are assuring that it is a function. If we graph the negative values, the graph is a parabola which opens to the right. This would not pass the vertical line test and would not be a function. Therefore the graph of the function f(x) = √x are only the values in the first quadrant.

Knowing the graph of the basic square root function, f(x) = √x, will help us graph many other radical functions. If h > 0, then f(x) = √(x +h) and f(x) = √(x - h) are the graphs of f(x) = √x moved to the left and right h units, respectively. For example, the graph of f(x) = √(x + 1) has an x-intercept is (-1, 0). When x = 0, f(x) = 1. The domain is x ≥ -1 because x < -1 will yield a negative under the radical and the square root of a negative is not a real number. You can plot several other points that makes √(x + 1) a perfect square. This graph is the graph of f(x) = √x moved 1 unit to the left. It is said to be translated 1 unit to the left. The graph of f(x) = √(x - 1), similarly, would be the graph of f(x) = √x moved 1 unit to the right.

We learned how to graph radical functions that are translations left and right of the square root function, f(x) = √x. Now we will learn how to graph radical functions that are that translations up and down of the square root function f(x) = √x. If k >0 , then f(x) = √x - k and f(x) = √x + k are the graphs of f(x) moved down k units and up k units, respectively. Therefore the graph of f(x) = √x + 3 is the same as the graph of f(x) = √x except it is translated 3 units up. Similarly, the graph of f(x) = √x - 3 is the same as the graph of f(x) = √x except it is translated 3 units down.

A function can have multiple translations. For example, the graph of f(x) = √(x - 2) + 1 is the same as the graph of f(x) = √x except it is translated 2 units right and 1 unit up. You will notice when graphing that there is vertical line through x = 2. The domain of the function is x ≥ 2. This shows that there are no points on the graph to the left of 2 on the x axis. The graph is in the first quadrant where both x and f(x) are positive.

The cube root function is a radical function defined as f(x) =

^{3}√x. To graph the function we want to choose values for x that are a perfect cube. For example 1 is a perfect cube because 1(1)(1) = 1 and 8 is a perfect cube because (2)(2)(2) = 8.

To graph f(x) =

^{3}√x, we'll set up a table of values.

Fox x = 1, f(1) =

^{3}√(1) = 1

x = -1, f(-1) =

^{3}√(-1) = -1

x = 8, f(8) =

^{3}√(8) = 2

x = -8, f(-8) =

^{3}√(-8) = -2

x = 27, f(27) =

^{3}√(27) = 3

x = -27, f(-27) =

^{3}√(-27) = -3

The function contains values in the first and third quadrants and no values in the second and fourth

quadrants. As with the square root function, there are translations with the cube root function. The graph of f(x) =

^{3}√x - 3 is the same as the graph of this function is the same the graph of f(x) =

^{3}√x except it is translated down 3 units.

This guide should help clear any confusion on the topic of radical functions and graphing radical functions.

## No comments:

## Post a Comment